00:01
We are looking at the proportion of flights that arrive on time at denver international airport.
00:05
We have a sample of 14 flights and we expect 85 % of them to be on time.
00:12
So probability of each being on time, 0 .85.
00:16
What is the probability for part a that they are all on time? so the key here is that we have to assume these are independent trials.
00:24
So that each flight is not affecting the others.
00:28
And because of that, we can combine the probabilities by multiplicating.
00:31
So for each flight, probability being on time is 0 .85, multiply it by itself 14 times, to get the probability that all of them are on time.
00:43
So that is 0 .10 to 8 to 4 decimal places.
00:50
Part b, the probability that's exactly 12 are on time.
00:54
So this becomes a bit more complicated.
00:57
And i'm going to use the binomial formula here, because this is a binomial distribution.
01:02
Independent trials, two outcomes per trial, one time or not, same probability for each.
01:08
0 .85 being on time for each plane.
01:13
Probability that exactly x are on time is n choose x, p to the x, 1 minus p to the n minus x.
01:21
So for 12, this term is for the 12 better on time.
01:27
0 .85, multiplied by itself 12 times.
01:30
This is for the 2 better not.
01:34
They're part of a 15 % multiplied by itself.
01:38
But this is now the probability that the first 12 planes are on time and the next two are delayed.
01:45
That's 12 out of 14, but it's not the only order that might happen in.
01:49
There are many different orders of on time and delayed that you could put these planes in.
01:54
And we have to account for all of them, because they're all 12 out of 14.
01:58
This term tells you how many orders there are.
02:01
So it's 14 choose 12, your calculator should have a button like this.
02:05
14 choose 12 is 91.
02:11
Now this product is the probability of exactly 12 being one time, which is 0 .29 -1 -2...