00:01
In the question it has been given that a team has developed a new non -toxic liquid named loop.
00:13
So in the question number one, there is the equation p equals to p -not plus row g d.
00:22
Basically p is here the pressure, that is absolute pressure.
00:28
For example, let's suppose this is the swimming pool and this is the liquid.
00:34
Then p -not is the pressure at the surface of the liquid and p is the pressure at the depth d that is d is here density sorry d is here the depth from the surface g is the acceleration due to gravity and row is the density so with depth p will be equals to p -0 plus density into acceleration due to gravity into depth.
01:24
Now in the second part of the question it has been asked.
01:28
To find the depth, one has to dive to experience the same total pressure felt at the depth of 3 to 8 meter in real water.
01:41
So let's say for 3 meter deep in water, pressure will be p equals to p p .0 plus row water that is density of water into g into depth that is equal to three meter.
02:07
Now similarly for gloop p will be equal to p .0 plus row that is the density of the gloop into g into h.
02:20
Now equating this p1 and p2 we will have p .0 plus row water into g into 3 equals to p .0 plus row gloop into g into h.
02:40
So p .0 p .0 will cancel out.
02:45
H will be equal to row water, that is let's say, row w into 3 divided by row g, that is row density of the gloop.
03:02
Now we know that density of water is 1000 into 3.
03:10
And let's suppose density of gloup is average 3 ,000 because it has been asked to choose from 2 ,000 to 4 ,000 so we have chosen here 3 ,000 so h will be here comes equal to 1 meter.
03:29
That means for water one has to go up to depth of 3 meter to fill the same pressure one has to go into gloop up to 1 meter only.
03:47
Now this is because the more density of the glupe fluid.
03:57
Now in the part 3 of the question it has asked if a mobile screen has been dropped into the big tank of gloop, then we have to find the amount of force the liquid will exert on the device screen.
04:17
We know that p is given as p0 plus r, rho d, so let's assume that p0 is here atmospheric pressure that is 101 .325 kilo pascal.
04:39
Now let's suppose depth is taken as 3 meter.
04:48
Density of the glup is taken as 3 ,000 kg per meter cube and g we all know that 9 .81.
04:59
So at the depth of 3 meter the ultimate pressure will be p equals to 101.
05:05
325 plus 3 ,000 into 3 into 9 .81.
05:15
That comes equals to 189 .1 kilo pascal...