Select the best answer for the question. 4. You're doing a...

Select the best answer for the question. 4. You're doing a PM inspection on a small chain-drive system. You see one side of the sprockets is shiny while the opposite side is dull. This means that the A. sprockets are worn. B. sprockets are misaligned. C. chain is the wrong size. D. chain is worn. Mark for review (Will be highlighted on the review page)

Transcript

00:01 So let us start with the concept which we are going to use here for this question.

00:07 So during the rotational motion we know that v becomes is equals to the r into omega where r will be the radius and omega is the angle of velocity.

00:18 So according to the question let's suppose the diagram.

00:20 So this is what the diagram in which you can see that it's indicating the sprocket okay or you will see the bicycle chain sprocket diagram.

00:33 So these are nothing but the velocities at point one and at point two.

00:38 This is omega of r, this is r of f radius, this is r of r radius and this is omega of f angular velocity.

00:48 So in this sprocket you will say there is a chain that is wrapped around the sprocket.

00:54 So when front sprocket rotates the chain rotates the rear sprocket and in this way the velocity of all the point on the periphery of both sprockets will be the same.

01:06 And hence we can say that the velocity at r will be equals to velocity at f.

01:12 Now let us equate it by using the above formula.

01:15 So we can say that this will become r of r into the angular velocity point r that is omega of r this should be equals to what that is r of f into the omega of f simple.

01:32 So by using this we can form the ratio as omega r by omega f.

01:38 So this should be equals to the r of f divided by the r of r okay r of f divided by r of r.

01:47 So this will be the required solution for a part of equation okay.

01:54 Now let's have a look b part.

01:56 So in the b part we will write down the above expression or we will carry it out this that is we will say omega r by omega of f is equals to r f divided by the r r...

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