00:01
So in this problem, we're flying a plane from joint -based lewis mccord.
00:08
So we're up here at j .b .l .m.
00:13
We're going to some undisclosed location.
00:17
And it's this point down here, right? we're flying to this point.
00:23
And it is 397 kilometers south and 240 kilometers.
00:40
East.
00:43
Along the way, mount rainier is over here, just outside our flight path, and it is 40 kilometers south and 56 kilometers east from where we're at.
01:14
And we're going to be cruising at 800 kilometers per hour.
01:21
Okay, and want to know when this distance is the closest or the minimum.
01:35
Well, it's going to be at the minimum when this line through here is perpendicular to our flight path is when that's going to happen.
01:48
So let's write the equation for our flight path.
01:52
Well, if we say that this is where we're starting that's zero, right? then our flat path is y equals minus 397x over 240, right? okay.
02:18
So in other words, 240y equals minus 397x.
02:27
Okay, now then, this perpendicular line then, going through the point at mount rainier, has a negative inverse slope and so it is y minus 40 yeah right y minus y 1 is equal to m times x minus x1 point slope formula and the slope is a negative reciprocal of that so it's 240 over 397 times x minus 56 okay.
03:20
So multiply all this out.
03:25
Then i get 397y is equal to 240x minus 240 and then i'm going to add 40 to it.
04:00
This is supposed to be plus, wasn't it? yeah, because it's minus a minus.
04:05
That should have been plus.
04:06
Okay.
04:07
So then i'm going to subtract 40 from it...