Question

\[ y=y_{0}+\frac{1}{2}\left(v_{0 y}+v_{y}\right) t \] \[ \begin{array}{c} v_{y}=v_{0 y}-g t \\ y=y_{0}+v_{0 y} t-\frac{1}{2} g t^{2} \\ v_{y}^{2}=v_{0 y}^{2}-2 g\left(y-y_{0}\right) \end{array} \]

          \[
y=y_{0}+\frac{1}{2}\left(v_{0 y}+v_{y}\right) t
\]
\[
\begin{array}{c}
v_{y}=v_{0 y}-g t \\
y=y_{0}+v_{0 y} t-\frac{1}{2} g t^{2} \\
v_{y}^{2}=v_{0 y}^{2}-2 g\left(y-y_{0}\right)
\end{array}
\]

y=y0+(1)/(2)(v0 y+vy) t

vy=v0 y-g t

y=y0+v0 y t-(1)/(2) g t^2

vy^2=v0 y^2-2 g(y-y0)

Added by Darnell C.

Fundamentals of Differential Equations

R. Kent Nagle 9th Edition

Chapter 4

Instant Answer

Solved by Expert Piyush Kumar Gupta

Step 1

- Equation 1: \( y = y_{0} + \frac{1}{2}(v_{0y} + v_{y})t \) - Equation 2: \( v_{y} = v_{0y} - gt \) - Equation 3: \( y = y_{0} + v_{0y}t - \frac{1}{2}gt^{2} \) - Equation 4: \( v_{y}^{2} = v_{0y}^{2} - 2g(y - y_{0}) \) Show more…

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\[ y=y_{0}+\frac{1}{2}\left(v_{0 y}+v_{y}\right) t \] \[ \begin{array}{c} v_{y}=v_{0 y}-g t \\ y=y_{0}+v_{0 y} t-\frac{1}{2} g t^{2} \\ v_{y}^{2}=v_{0 y}^{2}-2 g\left(y-y_{0}\right) \end{array} \]