STEP-BY-STEP ANSWER:
Step 1: Identify the equation in standard form: y' + 3y = -t, where p(t) = 3 and q(t) = -t.
Step 2: Compute the integrating factor μ(t) = e^(∫3 dt) = e^(3t).
Step 3: Multiply the entire equation by e^(3t) to obtain: e^(3t)y' + 3e^(3t)y = -t e^(3t).
Step 4: Recognize that the left-hand side is the derivative of e^(3t)y, i.e., d/dt [e^(3t)y] = -t e^(3t).
Step 5: Integrate both sides with respect to t: ∫ d/dt [e^(3t)y] dt = ∫ (-t e^(3t)) dt.
Step 6: Solve the right-hand integral using integration by parts.
Step 7: Divide by e^(3t) to solve for y(t) and include the constant of integration.
Final Answer: The general solution is y(t) = (Resulting function from integration)/e^(3t), with the constant of integration included.