Book cover for Calculus: Early Transcendentals

Calculus: Early Transcendentals

James Stewart

ISBN #9781285741550

8th Edition

6,422 Questions

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2,819,387 Students Helped

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Summary

Learning Objectives

Key Concepts

Example Problems

Explanations

Common Mistakes

Summary

This section on parametric equations highlights how curves can be described through a parameter, typically time, making it possible to analyze motion and direction along a curve. It explains methods to eliminate the parameter for transformation into Cartesian form and illustrates how different sets of parametric equations can describe the same curve. Moreover, real-world applications, such as projectile motion, cycloids, and CAD, demonstrate the versatility of parametric descriptions in both theoretical and practical settings.

Learning Objectives

1

Describe what parametric equations are and explain how they are used to represent curves, including those that fail the vertical line test.

2

Demonstrate how to eliminate the parameter to convert a set of parametric equations into a Cartesian equation.

3

Interpret the motion of a particle along a curve via its parametric equations, including the concepts of direction and variable speed.

4

Formulate parametric equations for common curves such as circles, parabolas, cycloids, and trochoids.

5

Apply parametric equations to real-world problems like projectile motion and computer-aided design (CAD) applications.

Key Concepts

CONCEPT

DEFINITION

Parametric Equations

A pair (or set) of equations where each coordinate (x, y, etc.) is expressed as a function of an independent parameter, usually denoted by t.

Parameter

An independent variable—typically time—that the coordinates depend on in order to define a trace or curve.

Parametric Curve

The set of points (x(t), y(t)) that are traced as the parameter t varies over a given interval.

Eliminating the Parameter

The process of removing the parameter from the parametric equations to yield a Cartesian equation in x and y.

Cycloid

The curve traced by a point on the circumference of a circle as the circle rolls along a straight line.

Trochoid

A generalization of a cycloid; it is the curve traced by a point at a fixed distance from the center of a rolling circle.

Conchoid

A family of curves generated by specific parametric equations, often resembling the shape of a conch or mussel shell.

Example Problems

Example 1

Sketch the curve by using the parametric equations to plot points. Indicate with an arrow the direction in which the curve is traced as $ t $ increases. $ x = 1 - t^2 $, $ \quad y = 2t - t^2 $, $ \quad -1 \leqslant t \leqslant 2 $

Example 2

Sketch the curve by using the parametric equations to plot points. Indicate with an arrow the direction in which the curve is traced as $ t $ increases. $ x = t^3 + t $, $ \quad y = t^2 + 2 $, $ \quad -2 \leqslant t \leqslant 2 $

Example 3

Sketch the curve by using the parametric equations to plot points. Indicate with an arrow the direction in which the curve is traced as $ t $ increases. $ x = t + \sin t $, $ \quad y = \cos t $, $ \quad -\pi \leqslant t \leqslant \pi $

Example 4

Sketch the curve by using the parametric equations to plot points. Indicate with an arrow the direction in which the curve is traced as $ t $ increases. $ x = e^{-a} + t $, $ \quad y = e^a - t $, $ \quad -2 \leqslant t \leqslant 2 $

Example 5

(a) Sketch the curve by using the parametric equations to plot points. Indicat with an arrow the direction in which the curve is traced as $ t $ increases. (b) Eliminate the parameter to find a Cartesian equation of the curve. $ x = 2t - 1 $, $ \quad y = \dfrac{1}{2}t + 1 $

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Step-by-Step Explanations

QUESTION

Given the parametric equations x = t^2 - 2t and y = t + 1, how do you eliminate t to find a Cartesian equation?

STEP-BY-STEP ANSWER:

Step 1: Solve the simpler equation for t. Here, y = t + 1 gives t = y - 1.
Step 2: Substitute t = y - 1 into the x-equation: x = (y - 1)^2 - 2(y - 1).
Step 3: Expand the equation: x = (y^2 - 2y + 1) - 2y + 2.
Step 4: Combine like terms: x = y^2 - 4y + 3.
Final Answer: The Cartesian equation is x = y^2 - 4y + 3.

Eliminating the Parameter (Example 1: Parabola)

QUESTION

How can you derive parametric equations for a circle with center (h, k) and radius r?

STEP-BY-STEP ANSWER:

Step 1: Start with the standard equation of a circle: (x - h)^2 + (y - k)^2 = r^2.
Step 2: Set x = h + r cos t and y = k + r sin t, using the trigonometric identities.
Step 3: Verify by substituting these into the circle's equation, which simplifies to r^2 (cos^2 t + sin^2 t) = r^2.
Final Answer: The parametric equations for the circle are x = h + r cos t and y = k + r sin t, with 0 ≤ t < 2π.

Deriving Parametric Equations for a Circle

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Common Mistakes

  • Assuming the parameter always represents time, even when it may be a different independent variable.
  • Errors in algebra when eliminating the parameter, such as mismanaging square terms or sign errors.
  • Forgetting that different parametric representations can yield the same curve, and not accounting for direction or speed of motion.
  • Neglecting domain restrictions for the parameter, which can lead to plotting the full curve versus a segment.
  • Overlooking the importance of the order in which points are traced, which is critical in applications like modeling motion.