STEP-BY-STEP ANSWER:
Step 1: Recognize that the square root is defined when its argument is nonnegative; therefore, set 9 − x² − y² ≥ 0.
Step 2: Rearrange the inequality to x² + y² ≤ 9. This describes a disk in the xy-plane with radius 3 centered at the origin.
Step 3: The domain of t is all points (x, y) such that x² + y² ≤ 9.
Step 4: Since square roots yield nonnegative outputs, the range is 0 ≤ t(x, y) ≤ 3, with the maximum value 3 occurring at (0,0).
Final Answer: Domain = {(x, y) ∈ ℝ² | x² + y² ≤ 9} and Range = [0, 3].