STEP-BY-STEP ANSWER:
Step 1: Write the definition of the derivative: f'(c) = lim (Δx → 0) [f(c + Δx) – f(c)] / Δx.
Step 2: Substitute f(x) into the formula: f(c + Δx) = (c + Δx)³ – 2(c + Δx) and f(c) = c³ – 2c.
Step 3: Expand (c + Δx)³ to get c³ + 3c²Δx + 3c(Δx)² + (Δx)³, and expand –2(c + Δx) to get –2c – 2Δx.
Step 4: Compute the difference f(c + Δx) – f(c): [c³ + 3c²Δx + 3c(Δx)² + (Δx)³ – 2c – 2Δx] – [c³ – 2c] = 3c²Δx + 3c(Δx)² + (Δx)³ – 2Δx.
Step 5: Factor Δx from the numerator: Δx(3c² + 3cΔx + (Δx)² – 2).
Step 6: Divide by Δx: [3c² + 3cΔx + (Δx)² – 2].
Step 7: Take the limit as Δx approaches 0: f'(c) = 3c² – 2.
Final Answer: f'(c) = 3c² – 2, and for any x, f'(x) = 3x² – 2.