STEP-BY-STEP ANSWER:
Step 1: Compute the derivative of the function: f'(x) = 3x² + 6x - 9.
Step 2: Find the critical numbers by setting f'(x) = 0. Solve: 3x² + 6x - 9 = 0, which simplifies to x² + 2x - 3 = 0. Factor to get (x + 3)(x - 1) = 0 so that x = -3 and x = 1.
Step 3: Divide the real number line into intervals using the critical numbers: (-∞, -3), (-3, 1), and (1, ∞).
Step 4: Select test points from each interval (e.g., x = -4, 0, and 2) and evaluate f'(x) at these points.
Step 5: Determine the sign of f'(x) in each interval: f'(-4) > 0 (increasing), f'(0) < 0 (decreasing), and f'(2) > 0 (increasing).
Final Answer: f(x) is increasing on (-∞, -3) and (1, ∞), and decreasing on (-3, 1). The tangent line is horizontal at x = -3 and x = 1.