$$\text { Sum of } a_{n}=3 n-1: S_{n}=\frac{n(3 n+1)}{2}$$
The sum of the first $n$ terms of the sequence defined by $a_{n}=3 n-1=2,5,8,11, \ldots,(3 n-1), \ldots$ is
given by the formula shown. Find $S_{8}$ using the formula, then verify by direct calculation. Observing the results of Exercises 83 and $84,$ can you now state the sum formula for $a_{n}=3 n-0 ?$