When a peptide $Q$ with the amino acid analysis (A,F,G $_{2}$, I, K,N,P,R,S,Y) is treated with trypsin, three new peptides are formed (amino acid analysis in parentheses): $T 1(\mathrm{~A}, \mathrm{~F}, \mathrm{R}, \mathrm{S}) ; T 2(\mathrm{G}, \mathrm{I}, \mathrm{K}) ;$ and $T 3(\mathrm{G}, \mathrm{N}, \mathrm{P}, \mathrm{Y})$. When peptide $Q$ is treated with chymotrypsin, four peptides are formed: $C I(\mathrm{~A}, \mathrm{~N}, \mathrm{R}, \mathrm{S}, \mathrm{Y}) ; C 2(\mathrm{~F}, \mathrm{~K}) ; C 3(\mathrm{G}, \mathrm{I}) ;$ and $C 4(\mathrm{G}, \mathrm{P}) .$ What can you deduce about the order in which the
amino acids in $P$ are connected? Explain. What are the points of uncertainty?