Consider the pendulum below. Ignoring air resistance, the angular displacement of the pendulum from the vertical position, $\theta$, can be modeled as a sinusoid. ${ }^{18}$
The amplitude of the sinusoid is the same as the initial angular displacement, $\theta_{0},$ of the pendulum and the period of the motion is given by
$$
T=2 \pi \sqrt{\frac{l}{g}}
$$
where $l$ is the length of the pendulum and $g$ is the acceleration due to gravity.
(a) Find a sinusoid which gives the angular displacement $\theta$ as a function of time, $t$. Arrange things so $\theta(0)=\theta_{0}$
(b) In Exercise 40 section $5.3,$ you found the length of the pendulum needed in Jeff's antique Seth-Thomas clock to ensure the period of the pendulum is $\frac{1}{2}$ of a second. Assuming the initial displacement of the pendulum is $15^{\circ}$, find a sinusoid which models the displacement of the pendulum $\theta$ as a function of time, $t,$ in seconds.