(i) The following mapping equation in the above integral for $f_g(\theta)$,
$$
F(\theta, \psi)=2 \eta[\lambda(\theta, \varphi)]-\lambda(\theta, \varphi) \theta \cos \varphi=A(\theta)-\zeta(\theta) \cos \psi
$$
defines a function $\varphi(\psi)$. Use the approximation
$$
G(\theta, \psi)=\frac{\lambda(\theta, \varphi)}{\sqrt{\left|\chi^{\prime}[\lambda(\theta, \varphi)]\right|}}\left(\frac{\mathrm{d} \varphi}{\mathrm{d} \psi}\right) \simeq p(\theta)+q(\theta) \cos \psi
$$
to obtain the uniform Bessel approximation (Berry 1975; Connor 2004)
$$
f_g(\theta) \simeq \frac{\exp [\mathrm{i} A(\theta)-3 \mathrm{i} \pi / 4]}{k}\left(\frac{2 \pi \theta}{\sin \theta}\right)^{1 / 2}\left\{p(\theta) J_0[\zeta(\theta)]+\mathrm{i} q(\theta) J_0^{\prime}[\zeta(\theta)]\right\},
$$
where $J_0^{\prime}(z)=\mathrm{d} J_0 / \mathrm{d} z$.
(ii) Show that correspondence between the stationary phase points on the two sides of the mapping equation yields $\lambda_b(\theta)=\lambda(\theta, \pi)$ and $\lambda_c(\theta)=\lambda(\theta, 0)$, such the $\chi_b=-\theta$ and $\chi_c=\theta$ respectively, in terms of which
$$
\begin{aligned}
A(\theta) & =\frac{1}{2}\left[2 \eta_b+2 \eta_c+\left(\lambda_b-\lambda_c\right) \theta\right], \\
\zeta(\theta) & =\frac{1}{2}\left[2 \eta_b-2 \eta_c+\left(\lambda_b+\lambda_c\right) \theta\right], \\
p(\theta) & =\frac{1}{2}\left(\frac{\zeta(\theta)}{\theta}\right)^{1 / 2}\left[\left(\lambda_c /\left|\chi_c^{\prime}\right|\right)^{1 / 2}+\left(\lambda_b /\left|\chi_b^{\prime}\right|\right)^{1 / 2}\right], \\
q(\theta) & =\frac{1}{2}\left(\frac{\zeta(\theta)}{\theta}\right)^{1 / 2}\left[\left(\lambda_c /\left|\chi_c^{\prime}\right|\right)^{1 / 2}-\left(\lambda_b /\left|\chi_b^{\prime}\right|\right)^{1 / 2}\right] .
\end{aligned}
$$
[Hint: $\mathrm{d} \varphi / \mathrm{d} \psi$ may be deduced from the second derivative of the transformation identity (compare eqn (B.12)).