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NCERT Class 11 - Math

Parvin Sinclair, G.P. Dikshit

Chapter 8

Binomial Theorem - all with Video Answers

Educators

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Section 1

Introduction

05:11

Problem 1

Expand each of the expressions.
$$
(1-2 x)^{5}
$$

Anas Venkitta
Anas Venkitta
Numerade Educator
04:35

Problem 2

Expand each of the expressions.
$$
\left(\frac{2}{x}-\frac{x}{2}\right)^{5}
$$

Anas Venkitta
Anas Venkitta
Numerade Educator
05:44

Problem 3

Expand each of the expressions.
$$
(2 x-3)^{6}
$$

Anas Venkitta
Anas Venkitta
Numerade Educator
05:34

Problem 4

Expand each of the expressions.
$$
\left(\frac{x}{3}+\frac{1}{x}\right)^{5}
$$

Anas Venkitta
Anas Venkitta
Numerade Educator
05:52

Problem 5

Expand each of the expressions.
$$
\left(x+\frac{1}{x}\right)^{6}
$$

Anas Venkitta
Anas Venkitta
Numerade Educator
04:29

Problem 6

Using binomial theorem, evaluate each of the following:
$$
(96)^{3}
$$

Anas Venkitta
Anas Venkitta
Numerade Educator
05:09

Problem 7

Using binomial theorem, evaluate each of the following:
$$
(102)^{5}
$$

Anas Venkitta
Anas Venkitta
Numerade Educator
06:45

Problem 8

Using binomial theorem, evaluate each of the following:
$$
(101)^{4}
$$

Anas Venkitta
Anas Venkitta
Numerade Educator
06:20

Problem 9

Using binomial theorem, evaluate each of the following:
$$
(99)^{5}
$$

Anas Venkitta
Anas Venkitta
Numerade Educator
02:01

Problem 10

Using Binomial Theorem, indicate which number is larger $(1.1)^{10000}$ or 1000 .

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Viraj Gaggar
Numerade Educator
02:28

Problem 11

Find $(a+b)^{4}-(a-b)^{4} .$ Hence, evaluate $(\sqrt{3}+\sqrt{2})^{4}-(\sqrt{3}-\sqrt{2})^{4}$.

Vg
Viraj Gaggar
Numerade Educator
02:47

Problem 12

Find $(x+1)^{6}+(x-1)^{6} .$ Hence or otherwise evaluate $(\sqrt{2}+1)^{6}+(\sqrt{2}-1)^{6}$.

Vg
Viraj Gaggar
Numerade Educator
02:38

Problem 13

Show that $9^{n+1}-8 n-9$ is divisible by 64 , whenever $n$ is a positive integer.

Vg
Viraj Gaggar
Numerade Educator
01:09

Problem 14

Prove that $\sum_{r=0}^{n} 3^{r n} \mathrm{C}_{r}=4^{n} .$

Vg
Viraj Gaggar
Numerade Educator