Suppose we have a mixture of the gases $\mathrm{H}_{2}(g)$, $\mathrm{CO}_{2}(g), \mathrm{CO}(g)$, and $\mathrm{H}_{2} \mathrm{O}(g)$ at $1260 \mathrm{~K}$, with $P_{\mathrm{H}_{2}}=$
$0.55$ bar, $P_{\mathrm{CO}_{2}}=0.20$ bar, $P_{\infty O}=1.25$ bar, and $P_{\mathrm{H}_{2} \mathrm{O}}=$
$0.10$ bar. Is the reaction described by the equation
$$
\mathrm{H}_{2}(g)+\mathrm{CO}_{2}(g) \leftrightharpoons \mathrm{CO}(g)+\mathrm{H}_{2} \mathrm{O}(g) \quad K_{\mathrm{p}}=1.59
$$
at equilibrium under these conditions? If not, in what direction will the reaction proceed to attain equilibrium?