(From a homework set in a graduate course in synaptic physiology) As a result of a complex set of biochemical reactions, the cell membrane of a nerve cell pumps ions $\left(\mathrm{Na}^{+}\right.$ and $\left.\mathrm{K}^{+}\right)$ back and forth across itself, thereby maintaining an electrostatic potential difference from the inside to the outside of the membrane. Modifications on the conditions can result in changes in those potentials. Part of the process can be modeled by treating the membrane as if it were a simple electric circuit consisting of batteries, resistors, and a switch. A simple model of the membrane of $\underline{a}$ nerve cell is shown in Fig. $27-68$. It consists of two batteries (ion pumps) with voltages $\Delta V_{1}=$ $100 \mathrm{mV}$ and $V_{2}=50 \mathrm{mV}$. The resistance to flow across the membrane is represented by two resistors with resistances $R_{1}=10 \mathrm{~K} \Omega$ and $R_{2}=90 \mathrm{~K} \Omega$. The variability is represented by a switch, $S_{1}$.
Four points on the circuit are labeled by the letters $a-d$. The point $b$ represents the outside of the membrane and the point $d$ the inside of the membrane.
(a) What is the voltage difference across the membrane (i.e., between $d$ and $b$ ) when the switch is open?
(b) What is the current flowing around the loop when the switch is closed?
(c) What is the voltage drop across the resistor $R_{1}$ when the switch is open? Closed?
(d) What is the voltage drop across the resistor $R_{2}$ when the switch is open? Closed?
(e) What is the potential difference across the membrane (i.e., between $d$ and $b$ ) when the switch is closed?
(f) If the locations of resistances $R_{1}$ and $R_{2}$ were reversed, would the voltages across the cell membrane be different?