The two sets of points $z=a, z=b, z=c$, and $z=A, z=B, z=C$ are the corners of two similar triangles in the Argand diagram. Express in terms of $a, b, \ldots, C$
(a) the equalities of corresponding angles, and
(b) the constant ratio of corresponding sides,
in the two triangles.
By noting that any complex quantity can be expressed as
$$
z=|z| \exp (i \arg z)
$$
deduce that
$$
a(B-C)+b(C-A)+c(A-B)=0
$$