In Exercises $1-4,$ use the grid and a straight edge to make a rough

estimate of the slope of the curve (in $y$ -units per $x$ -unit) at the points

$P_{1}$ and $P_{2}$ .

Check back soon!

Use the grid and a straight edge to make a rough

estimate of the slope of the curve (in $y$ -units per $x$ -unit) at the points

$P_{1}$ and $P_{2}$ .

Check back soon!

estimate of the slope of the curve (in $y$ -units per $x$ -unit) at the points

$P_{1}$ and $P_{2}$ .

Check back soon!

estimate of the slope of the curve (in $y$ -units per $x$ -unit) at the points

$P_{1}$ and $P_{2}$ .

Check back soon!

In Exercises $5-10,$ find an equation for the tangent to the curve at the

given point. Then sketch the curve and tangent together.

\begin{equation}

y=4-x^{2}, \quad(-1,3)

\end{equation}

Caleb E.

Numerade Educator

Find an equation for the tangent to the curve at the given point. Then sketch the curve and tangent together.

\begin{equation}

y=(x-1)^{2}+1, \quad(1,1)

\end{equation}

Madi S.

Numerade Educator

Find an equation for the tangent to the curve at the given point. Then sketch the curve and tangent together.

\begin{equation}

y=2 \sqrt{x}, \quad(1,2)

\end{equation}

Check back soon!

Find an equation for the tangent to the curve at the given point. Then sketch the curve and tangent together.

\begin{equation}

y=\frac{1}{x^{2}}, \quad(-1,1)

\end{equation}

Check back soon!

Find an equation for the tangent to the curve at the given point. Then sketch the curve and tangent together.

\begin{equation}

y=x^{3}, \quad(-2,-8)

\end{equation}

Alex R.

Numerade Educator

Find an equation for the tangent to the curve at the given point. Then sketch the curve and tangent together.

\begin{equation}

y=\frac{1}{x^{3}}, \quad\left(-2,-\frac{1}{8}\right)

\end{equation}

Check back soon!

In Exercises $11-18,$ find the slope of the function's graph at the given point. Then find an equation for the line tangent to the graph there.

\begin{equation}

f(x)=x^{2}+1, \quad(2,5)

\end{equation}

Justin P.

Numerade Educator

Find the slope of the function's graph at the given point. Then find an equation for the line tangent to the graph there.

\begin{equation}

f(x)=x-2 x^{2}, \quad(1,-1)

\end{equation}

Isabelle M.

Numerade Educator

Find the slope of the function's graph at the given point. Then find an equation for the line tangent to the graph there.

\begin{equation}

g(x)=\frac{x}{x-2}, \quad(3,3)

\end{equation}

Check back soon!

Find the slope of the function's graph at the given point. Then find an equation for the line tangent to the graph there.

\begin{equation}

g(x)=\frac{8}{x^{2}}, \quad(2,2)

\end{equation}

Ioannis S.

Numerade Educator

Find the slope of the function's graph at the given point. Then find an equation for the line tangent to the graph there.

\begin{equation}

h(t)=t^{3}, \quad(2,8)

\end{equation}

Tyler P.

Numerade Educator

Find the slope of the function's graph at the given point. Then find an equation for the line tangent to the graph there.

\begin{equation}

h(t)=t^{3}+3 t, \quad(1,4)

\end{equation}

Check back soon!

Find the slope of the function's graph at the given point. Then find an equation for the line tangent to the graph there.

\begin{equation}

f(x)=\sqrt{x}, \quad(4,2)

\end{equation}

Check back soon!

Find the slope of the function's graph at the given point. Then find an equation for the line tangent to the graph there.

\begin{equation}

f(x)=\sqrt{x+1},(8,3)

\end{equation}

Check back soon!

In Exercises $19-22,$ find the slope of the curve at the point indicated.

\begin{equation}

y=5 x-3 x^{2}, \quad x=1

\end{equation}

William C.

Numerade Educator

Find the slope of the curve at the point indicated.

\begin{equation}

y=x^{3}-2 x+7, \quad x=-2

\end{equation}

Check back soon!

Find the slope of the curve at the point indicated.

\begin{equation}

y=\frac{1}{x-1}, \quad x=3

\end{equation}

Check back soon!

Find the slope of the curve at the point indicated.

\begin{equation}

y=\frac{x-1}{x+1}, \quad x=0

\end{equation}

Check back soon!

Growth of yeast cells $\operatorname{In}$ a controlled laboratory experiment,

yeast cells are grown in an automated cell culture system that

counts the number $P$ of cells present at hourly intervals. The number after $t$ hours is shown in the accompanying figure.

\begin{equation}

\begin{array}{l}{\text { a. Explain what is meant by the derivative } P^{\prime}(5) . \text { What are its }} \\ {\text { units? }} \\ {\text { b. Which is larger, } P^{\prime}(2) \text { or } P^{\prime}(3) ? \text { Give a reason for your }} \\ {\text { answer. }}\end{array}

\end{equation}

\begin{equation}

\begin{array}{l}{\text { c. The quadratic curve capturing the trend of the data points }} \\ {\text { (see Section } 1.4 ) \text { is given by } P(t)=6.10 t^{2}-9.28 t+16.43} \\ {\text { Find the instantaneous rate of growth when } t=5 \text { hours. }}\end{array}

\end{equation}

Check back soon!

Effectiveness of a drug On a scale from 0 to 1, the effectiveness $E$ of a pain-killing drug $t$ hours after entering the bloodstream is displayed in the accompanying figure.

\begin{equation}

\begin{array}{l}{\text { a. At what times does the effectiveness appear to be increasing? }} \\ {\text { What is true about the derivative at those times? }} \\ {\text { b. At what time would you estimate that the drug reaches its }} \\ {\text { maximum effectiveness? What is true about the derivative at }} \\ {\text { that time? What is true about the derivative as time increases }} \\ {\text { in the } 1 \text { hour before your estimated time? }}\end{array}

\end{equation}

Check back soon!

At what points do the graphs of the functions in Exercises 25 and 26 have horizontal tangents?

\begin{equation}

f(x)=x^{2}+4 x-1

\end{equation}

Lukas M.

Numerade Educator

At what points do the graphs of the functions in Exercises 25 and 26 have horizontal tangents?

\begin{equation}

g(x)=x^{3}-3 x

\end{equation}

Aditya P.

Numerade Educator

Find equations of all lines having slope $-1$ that are tangent to the

curve $y=1 /(x-1)$ .

Eden B.

Numerade Educator

Find an equation of the straight line having slope 1$/ 4$ that is tangent to the curve $y=\sqrt{x} .$

Check back soon!

Object dropped from a tower An object is dropped from the

top of a $100-$ m-high tower. Its height above ground after $t$ sec is

$100-4.9 t^{2}$ m. How fast is it falling 2 sec after it is dropped?

Check back soon!

Speed of a rocket $A t t$ sec after liftoff, the height of a rocket is

3$t^{2}$ ft. How fast is the rocket climbing 10 sec after liftoff?

Jacinta H.

Numerade Educator

Circle's changing area What is the rate of change of the area

of a circle $\left(A=\pi r^{2}\right)$ with respect to the radius when the radius

is $r=3 ?$

Marc S.

Numerade Educator

Ball's changing volume

ume of a ball $\left(V=(4 / 3) \pi r^{3}\right)$ with respect to the radius when

the radius is $r=2 ?$

Keshav M.

Numerade Educator

Show that the line $y=m x+b$ is own tangent line at any

point $\left(x_{0}, m x_{0}+b\right)$

Carey H.

Numerade Educator

Find the slope of the tangent to the curve $y=1 / \sqrt{x}$ at the point

where $x=4 .$

Joshua W.

Numerade Educator

Does the graph of

\begin{equation}

f(x)=\left\{\begin{array}{ll}{x^{2} \sin (1 / x),} & {x \neq 0} \\ {0,} & {x=0}\end{array}\right.

\end{equation}

have a tangent at the origin? Give reasons for your answer.

Cody D.

Numerade Educator

Does the graph of

\begin{equation}

g(x)=\left\{\begin{array}{ll}{x \sin (1 / x),} & {x \neq 0} \\ {0,} & {x=0}\end{array}\right.

\end{equation}

have a tangent at the origin? Give reasons for your answer.

We say that a continuous curve $y=f(x)$ has a vertical tangent at the

point where $x=x_{0}$ if the limit of the difference quotient is $\infty$ or $-\infty$ .

For example, $y=x^{1 / 3}$ has a vertical tangent at $x=0$ (see accompanying figure):

\begin{equation}

\begin{aligned} \lim _{h \rightarrow 0} \frac{f(0+h)-f(0)}{h} &=\lim _{h \rightarrow 0} \frac{h^{1 / 3}-0}{h} \\ &=\lim _{h \rightarrow 0} \frac{1}{h^{2 / 3}}=\infty \end{aligned}

\end{equation}

However, $y=x^{2 / 3}$ has no vertical tangent at $x=0$ (see next figure):

\begin{equation}

\begin{aligned} \lim _{h \rightarrow 0} \frac{g(0+h)-g(0)}{h} &=\lim _{h \rightarrow 0} \frac{h^{2 / 3}-0}{h} \\ &=\lim _{h \rightarrow 0} \frac{1}{h^{1 / 3}} \end{aligned}

\end{equation}

Check back soon!

Does the graph of

\begin{equation}

f(x)=\left\{\begin{array}{cc}{-1,} & {x<0} \\ {0,} & {x=0} \\ {1,} & {x>0}\end{array}\right.

\end{equation}

have a vertical tangent at the origin? Give reasons for your answer.

Check back soon!

Does the graph of

\begin{equation}

U(x)=\left\{\begin{array}{ll}{0,} & {x<0} \\ {1,} & {x \geq 0}\end{array}\right.

\end{equation}

have a vertical tangent at the point $(0,1) ?$ Give reasons for your

answer.

Sophia G.

Numerade Educator

Graph the curves in Exercises $39-48$

\begin{equation}

\begin{array}{l}{\text { a. Where do the graphs appear to have vertical tangents? }} \\ {\text { b. Confirm your findings in part (a) with limit calculations. But }} \\ {\text { before you do, read the introduction to Exercises } 37 \text { and } 38 .}\end{array}

\end{equation}

\begin{equation}

y=x^{2 / 5}

\end{equation}

Check back soon!

Graph the curves.

\begin{equation}\begin{array}{l}{\text { a. Where do the graphs appear to have vertical tangents? }} \\ {\text { b. Confirm your findings in part (a) with limit calculations. But }} \\ {\text { before you do, read the introduction to Exercises } 37 \text { and } 38 .}\end{array}\end{equation}

\begin{equation}

y=x^{4 / 5}

\end{equation}

Check back soon!

Graph the curves.

\begin{equation}\begin{array}{l}{\text { a. Where do the graphs appear to have vertical tangents? }} \\ {\text { b. Confirm your findings in part (a) with limit calculations. But }} \\ {\text { before you do, read the introduction to Exercises } 37 \text { and } 38 .}\end{array}\end{equation}

\begin{equation}

y=x^{1 / 5}

\end{equation}

Check back soon!

Graph the curves.

\begin{equation}\begin{array}{l}{\text { a. Where do the graphs appear to have vertical tangents? }} \\ {\text { b. Confirm your findings in part (a) with limit calculations. But }} \\ {\text { before you do, read the introduction to Exercises } 37 \text { and } 38 .}\end{array}\end{equation}

\begin{equation}

y=x^{3 / 5}

\end{equation}

Check back soon!

Graph the curves.

\begin{equation}\begin{array}{l}{\text { a. Where do the graphs appear to have vertical tangents? }} \\ {\text { b. Confirm your findings in part (a) with limit calculations. But }} \\ {\text { before you do, read the introduction to Exercises } 37 \text { and } 38 .}\end{array}\end{equation}

\begin{equation}

y=4 x^{2 / 5}-2 x

\end{equation}

Check back soon!

Graph the curves.

\begin{equation}\begin{array}{l}{\text { a. Where do the graphs appear to have vertical tangents? }} \\ {\text { b. Confirm your findings in part (a) with limit calculations. But }} \\ {\text { before you do, read the introduction to Exercises } 37 \text { and } 38 .}\end{array}\end{equation}

\begin{equation}

y=x^{5 / 3}-5 x^{2 / 3}

\end{equation}

Sajin S.

Numerade Educator

Graph the curves.

\begin{equation}\begin{array}{l}{\text { a. Where do the graphs appear to have vertical tangents? }} \\ {\text { b. Confirm your findings in part (a) with limit calculations. But }} \\ {\text { before you do, read the introduction to Exercises } 37 \text { and } 38 .}\end{array}\end{equation}

\begin{equation}

y=x^{2 / 3}-(x-1)^{1 / 3}

\end{equation}

Check back soon!

Graph the curves.

\begin{equation}\begin{array}{l}{\text { a. Where do the graphs appear to have vertical tangents? }} \\ {\text { b. Confirm your findings in part (a) with limit calculations. But }} \\ {\text { before you do, read the introduction to Exercises } 37 \text { and } 38 .}\end{array}\end{equation}

\begin{equation}

y=x^{1 / 3}+(x-1)^{1 / 3}

\end{equation}

Check back soon!

Graph the curves.

\begin{equation}\begin{array}{l}{\text { a. Where do the graphs appear to have vertical tangents? }} \\ {\text { b. Confirm your findings in part (a) with limit calculations. But }} \\ {\text { before you do, read the introduction to Exercises } 37 \text { and } 38 .}\end{array}\end{equation}

\begin{equation}

y=\left\{\begin{array}{ll}{-\sqrt{|x|},} & {x \leq 0} \\ {\sqrt{x},} & {x>0}\end{array}\right.

\end{equation}

Check back soon!

Graph the curves.

\begin{equation}\begin{array}{l}{\text { a. Where do the graphs appear to have vertical tangents? }} \\ {\text { b. Confirm your findings in part (a) with limit calculations. But }} \\ {\text { before you do, read the introduction to Exercises } 37 \text { and } 38 .}\end{array}\end{equation}

\begin{equation}

y=\sqrt{|4-x|}

\end{equation}

Patrick V.

Numerade Educator

Use a CAS to perform the following steps for the functions in Exercises $49-52$ :

\begin{equation}\begin{array}{l}{\text { a. Plot } y=f(x) \text { over the interval }\left(x_{0}-1 / 2\right) \leq x \leq\left(x_{0}+3\right)} \\ {\text { b. Holding } x_{0} \text { fixed, the difference quotient }}\end{array}\end{equation}\begin{equation}

q(h)=\frac{f\left(x_{0}+h\right)-f\left(x_{0}\right)}{h}\end{equation}

at $x_{0}$ becomes a function of the step size $h .$ Enter this function into your CAS workspace.

\begin{equation}

\begin{array}{l}{\text { c. Find the limit of } q \text { as } h \rightarrow 0 \text { . }} \\ {\text { d. Define the secant lines } y=f\left(x_{0}\right)+q \cdot\left(x-x_{0}\right) \text { for } h=3,2} \\ {\text { and } 1 . \text { Graph them together with } f \text { and the tangent line over }} \\ {\text { the interval in part (a). }}\end{array}\end{equation}

\begin{equation}

f(x)=x^{3}+2 x, \quad x_{0}=0 \quad \text { 50. } f(x)=x+\frac{5}{x}, \quad x_{0}=1

\end{equation}

Check back soon!

Use a CAS to perform the following steps for the functions:

\begin{equation}\begin{array}{l}{\text { a. Plot } y=f(x) \text { over the interval }\left(x_{0}-1 / 2\right) \leq x \leq\left(x_{0}+3\right)} \\ {\text { b. Holding } x_{0} \text { fixed, the difference quotient }}\end{array}\end{equation}\begin{equation}

q(h)=\frac{f\left(x_{0}+h\right)-f\left(x_{0}\right)}{h}\end{equation}

at $x_{0}$ becomes a function of the step size $h .$ Enter this function into your CAS workspace.

\begin{equation}

\begin{array}{l}{\text { c. Find the limit of } q \text { as } h \rightarrow 0 \text { . }} \\ {\text { d. Define the secant lines } y=f\left(x_{0}\right)+q \cdot\left(x-x_{0}\right) \text { for } h=3,2} \\ {\text { and } 1 . \text { Graph them together with } f \text { and the tangent line over }} \\ {\text { the interval in part (a). }}\end{array}\end{equation}

\begin{equation}

f(x)=x+\sin (2 x), \quad x_{0}=\pi / 2

\end{equation}

Check back soon!

\begin{equation}\begin{array}{l}{\text { a. Plot } y=f(x) \text { over the interval }\left(x_{0}-1 / 2\right) \leq x \leq\left(x_{0}+3\right)} \\ {\text { b. Holding } x_{0} \text { fixed, the difference quotient }}\end{array}\end{equation}\begin{equation}

q(h)=\frac{f\left(x_{0}+h\right)-f\left(x_{0}\right)}{h}\end{equation}

at $x_{0}$ becomes a function of the step size $h .$ Enter this function into your CAS workspace.

\begin{equation}

\begin{array}{l}{\text { c. Find the limit of } q \text { as } h \rightarrow 0 \text { . }} \\ {\text { d. Define the secant lines } y=f\left(x_{0}\right)+q \cdot\left(x-x_{0}\right) \text { for } h=3,2} \\ {\text { and } 1 . \text { Graph them together with } f \text { and the tangent line over }} \\ {\text { the interval in part (a). }}\end{array}\end{equation}

\begin{equation}

f(x)=x+\sin (2 x), \quad x_{0}=\pi / 2

\end{equation}

Check back soon!

Use a CAS to perform the following steps for the functions:

\begin{equation}\begin{array}{l}{\text { a. Plot } y=f(x) \text { over the interval }\left(x_{0}-1 / 2\right) \leq x \leq\left(x_{0}+3\right)} \\ {\text { b. Holding } x_{0} \text { fixed, the difference quotient }}\end{array}\end{equation}\begin{equation}

q(h)=\frac{f\left(x_{0}+h\right)-f\left(x_{0}\right)}{h}\end{equation}

at $x_{0}$ becomes a function of the step size $h .$ Enter this function into your CAS workspace.

\begin{equation}

\begin{array}{l}{\text { c. Find the limit of } q \text { as } h \rightarrow 0 \text { . }} \\ {\text { d. Define the secant lines } y=f\left(x_{0}\right)+q \cdot\left(x-x_{0}\right) \text { for } h=3,2} \\ {\text { and } 1 . \text { Graph them together with } f \text { and the tangent line over }} \\ {\text { the interval in part (a). }}\end{array}\end{equation}

\begin{equation}

f(x)=\cos x+4 \sin (2 x), \quad x_{0}=\pi

\end{equation}

Check back soon!