Ampere defined classically the magnetic moment of electron owing to its orbital motion as the average over the orbit of $-e / 2(\mathbf{r} \times \mathbf{v})$.
Prove that our definition, $\mu=\partial E / \partial B_{0}$, reduces to this form by showing from (13.47) that
$$
\mu=-\frac{e}{2 m} \sum_{i} \mathbf{r}_{i} \times\left(\mathbf{p}_{i}-\frac{e}{2} \mathbf{r}_{i} \times \mathbf{B}_{0}\right)
$$
and
$$
\mathbf{v}_{i}=\frac{\partial \mathbf{H}}{\partial \mathbf{p}_{i}}=\frac{1}{m}\left(\mathbf{p}_{i}-\frac{e}{2} \mathbf{r}_{i} \times \mathbf{B}_{0}\right)
$$