The traditional "Moody-type" pipe friction correlation in Chap. 6 is of the form
$$
f=\frac{2 \Delta p D}{\rho V^{2} L}=\operatorname{fcn}\left(\frac{\rho V D}{\mu}, \frac{\varepsilon}{D}\right)
$$
where $D$ is the pipe diameter, $L$ the pipe length, and $\varepsilon$ the wall roughness. Note that pipe average velocity $V$ is used on both sides. This form is meant to find $\Delta p$ when $V$ is known. (a) Suppose that $\Delta p$ is known, and we wish to find $V$. Rearrange the above function so that $V$ is isolated on the left-hand side. Use the following data, for $\varepsilon / D=0.005,$ to make a plot of your new function, with your velocity parameter as the ordinate of the plot.
$$\begin{array}{c|c|c|c|c|c}
f & 0.0356 & 0.0316 & 0.0308 & 0.0305 & 0.0304 \\
\hline p V D / \mu & 15,000 & 75,000 & 250,000 & 900,000 & 3,330,000
\end{array}$$
(b) Use your plot to determine $V$, in $\mathrm{m} / \mathrm{s}$, for the following pipe flow: $D=5 \mathrm{cm}, \varepsilon=0.025 \mathrm{cm}, L=10 \mathrm{m},$ for water flow at $20^{\circ} \mathrm{C}$ and 1 atm. The pressure drop $\Delta p$ is $110 \mathrm{kPa}$