Figure $22-40$ shows a proton (p) on the central axis through a disk with a uniform charge density due to excess electrons. The disk is seen from an edge-on view. Three of those electrons are shown: electron $\mathrm{e}_{c}$ at the disk center and electrons $\mathrm{e}_{s}$ at opposite sides of the disk, at radius $R$ from the center. The proton is initially at distance $z=R=2.00 \mathrm{~cm}$ from the disk. At that location, what are the magnitudes of (a) the electric field $\vec{E}_{c}$ due to electron $\mathrm{e}_{c}$ and $(\mathrm{b})$ the $n e t$ electric field $\vec{E}_{s, \text { net }}$ due to electrons $\mathrm{e}_{s} ?$ The proton is then moved to $z=R / 10.0 .$ What then are the magnitudes of (c) $\vec{E}_{c}$ and (d) $\vec{E}_{s, \text { net }}$ at the proton's location? (e) From (a) and (c) we see that as the proton gets nearer to the disk, the magnitude of $\vec{E}_{c}$ increases, as expected. Why does the magnitude of $\vec{E}_{s, \text { net }}$ from the two side electrons decrease, as we see from (b) and (d)?