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Electromagnetic Fields and Waves: Including Electric Circuits

Paul Lorrain, Dale R. Corson

Chapter 8

Electric Fields Vi - all with Video Answers

Educators


Chapter Questions

02:17

Problem 1

The voltage at the terminals of a certain defective automobile battery drops from $12.5$ to $11.5$ volts when the headlights are turned on. What is the approximate value of the output resistance?

Vishal Gupta
Vishal Gupta
Numerade Educator
01:10

Problem 2

Show that the output resistance of the bridge circuit of Fig. $8-17$, as seen at the voltmeter $V$, is $R$. Assume that the source has a zero output resistance.

Yaqub Khan
Yaqub Khan
Numerade Educator
03:20

Problem 3

(a) Calculate the current that flows to the right through the resistance $R_{o}$ in Fig. 8-18. Use mesh currents and the KVL. The output resistance of the battery is negligible.
(b) Calculate the same current by Thévenin's theorem, considering the complete circuit minus $R_{o}$ as the source.

Sanjeev Kumar
Sanjeev Kumar
Numerade Educator
03:24

Problem 4

(a) Show that $V_{o}=I_{o} / Y_{o}$.
(b) Show that Eq. 8-4 is equivalent to Eq. 8-2.

Eric Mockensturm
Eric Mockensturm
Numerade Educator
01:43

Problem 5

Calculate the voltage across the resistance $R_{o}$ of Fig. 8-18 by Norton's theorem. The output conductance of the source is infinite.

Mirza  Aslam Beig
Mirza Aslam Beig
Numerade Educator
04:47

Problem 6

In the circuit of Fig. 8-19 the switch $S$ closes at $t=0$. Find the voltage $V_{C}$ across $C$ as a function of the time by means of Millman's theorem. Set $R_{1}=1 \mathrm{ohm}, R_{2}=2$ ohms, $R_{3}=3$ ohms, $C=1$ microfarad, $V=100$ volts.

Brandy Heflin
Brandy Heflin
Numerade Educator
00:56

Problem 7

(a) Show that Tellegen's theorem is a consequence of the KCL.
(b) Show that Tellegen's theorem is also a consequence of the KVL.

Varsha Aggarwal
Varsha Aggarwal
Numerade Educator
04:24

Problem 8

Check the last three reciprocity theorems of Fig. 8-11 by applying them to the simple circuit of Fig. 8-12(a).

Narayan Hari
Narayan Hari
Numerade Educator
04:17

Problem 9

Show that the ratio $I / V$ for the circuit of Fig. $8-20(\mathrm{a})$ is the same as for the circuit of Fig. 8-20(b). Find $Q(t)$ first.

Kajal Gautam
Kajal Gautam
Numerade Educator
01:54

Problem 10

An audio power amplifier has an output resistance of 8 ohms and feeds a resistive load of $6.4$ ohms. Calculate the efficiency.

Narayan Hari
Narayan Hari
Numerade Educator
04:18

Problem 11

Find the equations for either the delta-star or the star-delta transformation by assuming mesh currents as in Fig. $8-15$ and making the voltages $V_{A}-V_{B}, V_{B}-V_{C}, V_{C}-V_{A}$ in part $(a)$ the same as those in part (b)
Find an equation of the form $(\ldots) I_{A}+(\ldots) I_{B}+(\ldots) I_{C}=0 .$ Since this equation must be valid whatever the values of the mesh currents, the parentheses must all be identically equal to zero. This will give you one of the equations of one set; the other two equations follow by symmetry.

M Hassan Anwar
M Hassan Anwar
Numerade Educator
02:12

Problem 12

Find the resistance of the circuit shown in Fig. 8-21.

Vishal Gupta
Vishal Gupta
Numerade Educator
12:22

Problem 13

It is difficult to measure the conductivity of small samples of semiconductor. First, they are brittle and thus difficult to machine. Second, contacts to the material are resistive. With Van der Pauw's theorem, however, it is possible to measure the conductivity of a sample in the form of a thin plate of arbitrary shape with four contacts around the periphery without interference from the contact resistances. We deduce this theorem for the case of a semi-infinite plate.
(a) Imagine an infinite thin plate of thickness $s$ and conductivity $\sigma$. $A$. current $2 I$ flows into point $A$ in Fig. 8-22(a).

Show that, in the plate, $E=I / \pi \sigma r s$, where $r$ is the radial distance to $A$.
(b) Now consider three points $B, C, D$ as in Fig. 8-22(a), on a line going through $A$. Show that
$$
V_{C}-V_{D}=\frac{I}{\pi \sigma S} \ln \frac{a+b+c}{a+b}
$$
If we cut the plate along the line and remove the lower half, the above equation applies to the upper half, if $I$ is now the current at $A$ flowing into the upper half. So we now have a semi-infinite plate as in Fig. $8-22(b)$.
(c) Now suppose that a current $I$ comes out of $B$ as in Fig. 8-22(c). Calculate $V_{C}-V_{D}$ again; then superpose cases (b) and (c) to obtain Fig. $8-22(d)$. Show that, for case $(d)$
$$
\frac{V_{C}^{\prime}-V_{0}^{\prime}}{I}=\frac{1}{\pi \sigma s} \ln \frac{(a+b+c) b}{(a+b)(b+c)}
$$
This ratio has the dimensions of a resistance; call it $R_{A B, E D} .$ The contact resistances at $A$ and $B$ are unimportant because only the current $I$ between $A$ and $B$ is significant. The contact resistances at $C$ and $D$ are also unimportant if their sum is much smaller than the resistance of the voltmeter that measures $V_{C}-V_{D}$
(d) Show that, with currents as in Fig. 8-22(e),
$$
R_{k C, D A}=\frac{1}{\pi \sigma S} \ln \frac{(a+b)(b+c)}{a c}
$$
(e) You can now derive Van der Pauw's theorem:
$$
\exp \left(\pi_{D S} R_{A B, C D}\right)+\exp \left(\pi \sigma S R_{B C, D A}\right)=1
$$
The only unknown is $\sigma .$ This result, in fact, applies to a lamella of any shape, with contacts $A, B, C, D$ around the periphery.

Khoobchandra Agrawal
Khoobchandra Agrawal
Numerade Educator