At a point $P$, a distance $R_{0}$ from a positive charge $Q_{0}$, the electric field has a magnitude $E_{0}=100 \mathrm{~N} / \mathrm{C}$ and the electric potential is $V_{0}=10 \mathrm{~V}$. The charge is now increased by a factor of three, becoming $3 Q_{0}$. (a) At what distance, $R_{\mathrm{E}}$, from the charge $3 Q_{0}$ will the electric field have the same value, $E=E_{0}$; and
(b) at what distance, $R_{\mathrm{V}}$, from the charge $3 Q_{0}$ will the electric potential have the same value, $V=V_{0}$ ?