JEE Physics

StemEZ

Chapter 24

Experiment - Meter Scale - all with Video Answers

Educators

Chapter Questions

Problem 2791

When the moment of force is maximum, then what is the angle between force and position vector of the force?
(A) $90^{\circ}$
(B) $0^{\circ}$
(C) $30^{\circ}$
(D) $45^{\circ}$

Narayan Hari

Narayan Hari

Numerade Educator

Problem 2792

In the scale and wedge experiment, m situated at $\mathrm{x}$ from the wedge and $\mathrm{M}$ is situated at y from wedge at equilibrium. Now if $\mathrm{m}<\mathrm{M}$, then what is the relation between $\mathrm{x}$ and $\mathrm{y}$ ?
(A) $x=y$
(B) $x<y$
(C) $x>y$
(D) nothing can be said about $-\mathrm{x}$ and $\mathrm{y}$ unless values of $\mathrm{m}$ and $\mathrm{M}$ one know.

Narayan Hari

Numerade Educator

Problem 2793

When the "wedge and scale" experiment is performed at the equator, we get $m=M\left(y_{e} / x_{e}\right)$. If the same experiment is performed at the poles, then what is the right equation ?
(A) $\mathrm{m}=\mathrm{M}\left(\mathrm{y}_{\mathrm{e}} / \mathrm{x}_{\mathrm{e}}\right) \cdot\left(\mathrm{R}_{\mathrm{e}} / \mathrm{R}_{\mathrm{p}}\right)$
(B) $m=M\left(y_{e} / x_{e}\right) \cdot\left(R_{p} / R_{e}\right)$
(C) $\mathrm{m}=\mathrm{M}\left(\mathrm{y}_{\mathrm{e}} / \mathrm{x}_{\mathrm{e}}\right) \cdot\left(\mathrm{R}_{\mathrm{p}} / \mathrm{R}_{\mathrm{e}}\right)^{2}$
(D) $\mathrm{m}=\mathrm{M}\left(\mathrm{y}_{\mathrm{e}} / \mathrm{x}_{\mathrm{e}}\right)$
Where $\mathrm{R}_{\mathrm{e}}$ and $\mathrm{R}_{\mathrm{p}}$ are the equatorial and polar radius of the earth.

Narayan Hari

Numerade Educator

Problem 2794

A force $2 \mathrm{i} \wedge+3 \mathrm{j} \wedge$ acts about an axis at a position vector $(\mathrm{j} \wedge+\mathrm{k} \wedge)$ from the axis, then what is the torque due to the force about the axis?
(A) $\sqrt{19} \mathrm{Nm}$
(B) $\sqrt{13} \mathrm{Nm}$
(C) $\sqrt{15 \mathrm{Nm}}$
(D) $\sqrt{17} \mathrm{Nm}$

Narayan Hari

Numerade Educator

Problem 2795

In the experiment of balancing moments, suppose the fulcrum is at the $60 \mathrm{~cm}$ mark, and a known mass of $2 \mathrm{~kg}$ is used on the longer arm. The greatest mass of $\mathrm{m}$ which can be balanced against $2 \mathrm{~kg}$ such that the minimum distance of either of the masses from the fulcrum is at least $10 \mathrm{~cm}$. (Neglect mass of meter scale.) What will be the value of $\mathrm{m}$ ?
(A) $12 \mathrm{~kg}$
(B) $4 \mathrm{~kg}$
(C) $6 \mathrm{~kg}$
(D) $8 \mathrm{~kg}$

Narayan Hari

Numerade Educator

Problem 2796

The wedge is kept below the $60 \mathrm{~cm}$ mark on the meter scale. Known masses of $1 \mathrm{~kg}$ and $2 \mathrm{~kg}$ are hung at the $20 \mathrm{~cm}$ and $30 \mathrm{~cm}$ mark respectively. Where will a $4 \mathrm{~kg}$ mass be hung on the meter scale to balance it ? (Neglect mass of meter scale.)
(A) $85 \mathrm{~cm}$
(B) $90 \mathrm{~cm}$
(C) $70 \mathrm{~cm}$
(D) $75 \mathrm{~cm}$

Narayan Hari

Numerade Educator

Problem 2797

When a meter scale is balanced above a wedge, $1 \mathrm{~kg}$ mass is hung at $10 \mathrm{~cm}$ mark and a $2 \mathrm{~kg}$ mass is hang at the $85 \mathrm{~cm}$ mark. To which mark on the meter scale, the fulcrum be shifted (Neglect mass of meter scale) to balance the scale?
(A) $70 \mathrm{~cm}$
(B) $50 \mathrm{~cm}$
(C) $60 \mathrm{~cm}$
(D) $65 \mathrm{~cm}$

Narayan Hari

Numerade Educator