The resonant frequency of a quartz crystal is given by
$$
v_{0}=\frac{1}{2 l} \sqrt{\frac{Y}{\rho}}
$$
where $l$ is the dimension that determines the mode of oscillation of the crystal, $Y$ is the Young's modulus and $\rho$ is the density of quartz. Determine the useful sizes of the crystal for oscillators in $\mathrm{kHz}$ and $\mathrm{MHz}$ ranges (for quartz, $Y=10^{10} \mathrm{~N} \mathrm{~m}^{-2}, \rho=2500 \mathrm{~kg} \mathrm{~m}^{-3}$ ).