Show that the Frobenius mapping $\phi: \mathrm{GF}\left(p^{n}\right) \rightarrow \mathrm{GF}\left(p^{n}\right)$, given by $a \rightarrow a^{p}$, is a ring automorphism of order $n$ (that is, $\phi^{n}$ is the identity mapping). (This exercise is referred to in Chapter 32.)