At $45^{\circ}$ latitude, the gravitational acceleration as a function of elevation $z$ above sea level is given by $g=a-b z$, where $a=9.807 \mathrm{~m} / \mathrm{s}^2$ and $b=3.32 \times 10^{-6} \mathrm{~s}^{-2}$. Determine the height above sea level where the weight of an object will decrease by 1 percent. Answer: $29,539 \mathrm{~m}$