The conversion of compound 11.10 to its
(Z)-isomer (see Section 6.11) is induced by a flash of light (flash photolysis). Isomer 11.10 absorbs light at $435 \mathrm{nm},$ and the $(Z)$ -isomer absorbs at $316 \mathrm{nm} .$ Figure 11.11 shows the change in absorbance at $\lambda=435 \mathrm{nm}$ for a solution of 11.9 in cyclohexane over a period of 1200 s during which time the solution is subjected to a flash of light. (a) Rationalize the shape of the curve in Figure $11.11 .$ (b) If the path length of the solution cell is $1 \mathrm{cm},$ and the solution concentration is $9.00 \times 10^{-6} \mathrm{mol} \mathrm{dm}^{-3},$ determine a value for $\log \varepsilon$ corresponding to the absorption at $435 \mathrm{nm}$ [Data from: S. R. Hair et al. (1990) J. Chem. Ed., vol. $67, p .709 .]$
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