Consider a motion $\varphi: B \times[0, \infty) \rightarrow \mathbb{E}^{3}$. For any fixed $t \geq 0$ let $\boldsymbol{v}$ be the spatial velocity field in the current configuration $B_{t}$ and let $\boldsymbol{\psi}$ be the inverse motion. For any $s>0$ let $\widehat{\boldsymbol{\varphi}}_{s}: B_{t} \rightarrow B_{t+s}$ be the motion which coincides with $\varphi_{t+s}: B \rightarrow B_{t+s}$ in the sense that
$$
\widehat{\boldsymbol{\varphi}}(\boldsymbol{x}, s)=\left.\boldsymbol{\varphi}(\boldsymbol{X}, t+s)\right|_{\boldsymbol{X}=\boldsymbol{\psi}(\boldsymbol{x}, t)}, \quad \forall \boldsymbol{x} \in B_{t}
$$
(a) Show that $\widehat{\varphi}(\boldsymbol{x}, 0)=\boldsymbol{x}$ for all $\boldsymbol{x} \in B_{t}$.
(b) Show that $\frac{\partial}{\partial s} \widehat{\varphi}(\boldsymbol{x}, 0)=\boldsymbol{v}(\boldsymbol{x}, t)$ for all $\boldsymbol{x} \in B_{t}$.
(c) Let $\widehat{\boldsymbol{F}}(\boldsymbol{x}, s)=\nabla^{x} \widehat{\boldsymbol{\varphi}}(\boldsymbol{x}, s)$ be the deformation gradient associated with $\widehat{\varphi}$. Show that $\widehat{\boldsymbol{F}}(\boldsymbol{x}, 0)=\boldsymbol{I}$ and $\frac{\partial}{\partial s} \widehat{\boldsymbol{F}}(\boldsymbol{x}, 0)=\nabla^{x} \boldsymbol{v}(\boldsymbol{x}, t)$
(d) Let $\widehat{\boldsymbol{E}}=\operatorname{sym}\left(\nabla^{x} \widehat{\boldsymbol{u}}\right)=\operatorname{sym}(\widehat{\boldsymbol{F}}-\boldsymbol{I})$ be the infinitesimal strain tensor associated with $\widehat{\varphi}$. Show that
$$
\boldsymbol{L}(\boldsymbol{x}, t)=\frac{\partial}{\partial s} \widehat{\boldsymbol{E}}(\boldsymbol{x}, 0)
$$
(e) Consider the right polar decomposition $\widehat{\boldsymbol{F}}=\widehat{\boldsymbol{R}} \widehat{\boldsymbol{U}}$, where $\widehat{\boldsymbol{U}}^{2}=\widehat{\boldsymbol{F}}^{T} \widehat{\boldsymbol{F}} .$ Show that
$$
\boldsymbol{L}(\boldsymbol{x}, t)=\frac{\partial}{\partial s} \widehat{\boldsymbol{U}}(\boldsymbol{x}, 0), \quad \boldsymbol{W}(\boldsymbol{x}, t)=\frac{\partial}{\partial s} \widehat{\boldsymbol{R}}(\boldsymbol{x}, 0).
$$