Figure 29.58 shows a wire segment of length $\Delta s=3.0 \mathrm{~cm}$, centered at the origin, carrying current $i=2.0 \mathrm{~A}$ in the positive $y$ direction (as part of some complete circuit). To calculate the magnitude of the magnetic field $\vec{B}$ produced by the segment at a point several meters from the origin, we can use $B=$ $\left(\mu_0 / 4 \pi\right) i \Delta s(\sin \theta) / r^2$ as the BiotSavart law. This is because $r$ and $\theta$ are essentially constant over the segment. Calculate $\vec{B}$ (in unit-vector notation) at the $(x, y, z)$ coordinates (a) $(0,0,5.0 \mathrm{~m})$, (b) $(0,6.0 \mathrm{~m}, 0)$, (c) $(7.0 \mathrm{~m}, 7.0 \mathrm{~m}$, $0)$, and $(\mathrm{d})(-3.0 \mathrm{~m},-4.0 \mathrm{~m}, 0)$.