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Electromagnetic Fields and Waves: Including Electric Circuits

Paul Lorrain, Dale R. Corson

Chapter 24

Magnetic Fields Vii - all with Video Answers

Educators


Chapter Questions

04:26

Problem 1

The mutual inductance between a solenoid and a short coaxial coil A long solenoid of radius $R$ and $N^{\prime}$ turns per meter carries a short coil of $N$ turns near its center.
(a) Calculate the mutual inductance $M$.
(b) Does the radius of the short coil affect $M$ ?
Note how much more difficult it would be to calculate the flux linking the solenoid for a given current in the short coil.

Khoobchandra Agrawal
Khoobchandra Agrawal
Numerade Educator
02:53

Problem 2

The mutual inductance between a toroid and an axial wire
A long straight wire lies along the axis of a toroid of $N$ turns, major radius $a$, and square cross section of side $b$, with $a \gg b$.
Calculate the mutual inductance (a) assuming a current $I$ in the wire and (b) assuming a current $I$ in the toroid.

Keshav Singh
Keshav Singh
Numerade Educator
03:19

Problem 3

The mutual inductance between a straight wire and a loop A loop of wire of radius $R$ is centered at a distance $2 R$ from a long straight wire. The wire is in the plane of the loop.
Calculate the mutual inductance.

Keshav Singh
Keshav Singh
Numerade Educator
01:24

Problem 4

A zero-mutual-inductance magnetic dipole pair
A certain device for geophysical exploration comprises two short coils in the position shown in Fig. 24-10. The manufacturer states that the mutual, inductance is zero. Is that true?

Keshav Singh
Keshav Singh
Numerade Educator
00:47

Problem 5

Current transformer
Figure $24-11$ shows a side-look current transformer for measuring large current pulses. Show that for a single-turn coil
$$
V=\frac{\mu_{0} a}{\pi} \ln \left(\frac{b+a}{b-a}\right) \frac{d l}{d t}
$$
One can obtain $I(t)$ with an integrating circuit (Prob. 7-9).

Amy Jiang
Amy Jiang
Numerade Educator
01:01

Problem 6

A conducting shield for fluctuating magnetic fields
It is often necessary to shield instruments from stray magnetic fields. If the only disturbing field is that of the earth, then one can set up a pair of Helmholtz coils (Prob. 18-9) to oppose the earth's field. If the field is static but not uniform, then one must use a shield made of high-permeability material. Multiple shields, one inside the other, are better than a single thick shield.
Could a conducting enclosure be a good shield against fluctuating magnetic ficlds? The answer is yes, as we shall see, but only at quite high frequencies.
Imagine a simple situation where the external magnetic field $B_{e x}$ is uniform, with $B_{\mathrm{rz}}=B_{\text {es.m }}$ exp jot. The shield is a long tube, parallel to the lines of $\boldsymbol{B}$, a few times longer than its diameter $2 a$, and a few times longer than the shiclded region.
We assume that the current induced in the shield is uniformly distributed, throughout its thickness $b$. In other words, we disregard the skin effect, (Sec. 29.1). If this assumption is not valid, then the shielding is better than our calculation would indicate.
(a) Calculate the resistance $R$ ' of the tube, per unit length, in the azimuthal direction. Calculate $L$.
(b) Let $B_{m}=B_{\text {in, in }}$ exp jot be the value of $B$ inside the tube, away from the ends. Find the ratio $B_{\text {in. }} / B_{e x}, m$
(c) Show that, if the skin effect is negligible, this ratio cannot be smaller than $0.5$. A conducting enclosure therefore acts as a shield only through the skin effect.

Dominador Tan
Dominador Tan
Numerade Educator
04:50

Problem 7

Inductance and reluctance
An N-turn coil links a magnetic circuit. Show that $L=N^{2} \mathscr{M}$.

Vishal Gupta
Vishal Gupta
Numerade Educator
12:47

Problem 8

The Maxwell bridge
See Prob. 7-12. Figure 24-12 shows a Maxwell bridge. This circuit serves to measure the inductance $L$ and the resistance $R$ of an inductor. One adjusts the values of $R_{b}, R_{r}, R_{d}$, and $C$ until $V$ equals zero.
Find $L$ and $R$ in terms of the other components.

Ramesh Singh
Ramesh Singh
Numerade Educator
02:47

Problem 9

Electromagnet operating on alternating current
An electromagnet with a variable gap length operates on alternating current. How does the rms value of the magnetic flux depend on the gap length, for a given applied voltage, and neglecting leakage flux?

Abhishek Jana
Abhishek Jana
Numerade Educator
04:36

Problem 10

(24.2) Power-factor correction.
A load is inductive, has a power factor of $65 \%$, and draws a current of 100 amperes at 600 volts.
(a) Calculate the magnitude of $Z$, its phase angle, and its real and imaginary parts.
(b) Calculate the in-phase and quadrature components of the current.
(c) What size capacitor should be placed in parallel with the load to cancel the reactive current at 60 hertz?
(d) What is the current supplied by the source now?
Note that $Z^{\prime}$ is not equal to the real part of $Z$.

Mayukh Banik
Mayukh Banik
Numerade Educator
09:33

Problem 11

(24. 2.1) Power-factor correction with fluorescent lamps
A fiworescent lamp consists of an evacuated glass tube containing mercury vapor and coated on the inside with a fluorescent mixture. A discharge occurs between electrodes situated at each end. The discharge emits most of its energy at $253.7$ nanometers, in the ultraviolet. The fluorescent coating absorbs this radiation and reemits visible light.

The discharge operates correctly only when it is connected in serics with an impedance. A resistor would dissipate energy, so it is the custom to use a series inductor. Several types of circuit are in use.
One particular fluorescent fixture operates at 120 volts and dissipates 80 watts. Its power factor is $50 \%$.
(a) Find the reactive current.
(b) What is the size of the capacitor connected in parallel with the discharge tube and its inductor that will make the power factor equal to $100 \% ?$

Ben Nicholson
Ben Nicholson
Numerade Educator