Three different compounds have the same molecular formula, $\mathrm{C}_{2} \mathrm{H}_{2} \mathrm{~F}_{2} ;$ call them $\mathrm{A}, \mathrm{B}$, and $\mathrm{C}$. Compound $\mathrm{A}$ has a dipole moment of $2.42 \mathrm{D}$, compound $\mathrm{B}$ has a dipole moment of $1.38 \mathrm{D}$, and compound $\mathrm{C}$ has a dipole moment of $0 \mathrm{D} .$ All three compounds react with hydrogen, $\mathrm{H}_{2}$ :
$$\mathrm{C}_{2} \mathrm{H}_{2} \mathrm{~F}_{2}+\mathrm{H}_{2} \longrightarrow \mathrm{C}_{2}\mathrm{H}_{4} \mathrm{~F}_{2}$$
Compound A gives product D (molecular formula $\mathrm{C}_{2} \mathrm{H}_{4} \mathrm{~F}_{2}$ ), compound B gives product $E$ (same molecular formula, $\mathrm{C}_{2} \mathrm{H}_{4} \mathrm{~F}_{2}$, but different from product $\mathrm{D}$ ), and compound $\mathrm{C}$ gives product D. Identify the structural formulas of compounds $\mathrm{A}$, $\mathrm{B}$, and $\mathrm{C}$.