Given the following mass doublet values (in units of $10^{-t} \dot{u}$ ). compute the corresponding values for the atomic mass of ${ }^{37} \mathrm{Cl}$ :
$$
\begin{aligned}
m\left(\mathrm{C}_{3} \mathrm{H}\right)-m\left({ }^{37} \mathrm{Cl}\right) &=41922.2 \pm 0.3 \\
m\left(\mathrm{C}_{2} \mathrm{D}_{8}\right)-m\left({ }^{37} \mathrm{ClH}_{3}\right) &=123436.5 \pm 0.1 \\
m\left(\mathrm{C}_{3} \mathrm{H}_{6} \mathrm{O}_{2}\right)-m\left({ }^{37} \mathrm{Cl}_{2}\right) &=104974.24 \pm 0.08
\end{aligned}
$$
Here $D={ }^{2} \mathrm{H}, C={ }^{12} C$, and $O={ }^{16} O$. Include in your calculation the effect of uncertainties in the H, D, O, and C masses.