The base radius of a cone, $r$, is decreasing at the rate of $0-1 \mathrm{~cm} / \mathrm{s}$ while the perpendicular helght, $h$, is increasing at the rate of $0-2 \mathrm{~cm} / \mathrm{s}$. Pind the rate at which the volume, $V$, is changing when $r=2 \mathrm{~cm}$ and $h=3 \mathrm{~cm}$.