Chloroform, CHCl $_{3},$ is formed from methane and schlorine in the following reaction.
$$ \mathrm{CH}_{4}(\mathrm{g})+3 \mathrm{Cl}_{2}(\mathrm{g}) \rightarrow 3 \mathrm{HCl}(\mathrm{g})+\mathrm{CHCl}_{3}(\mathrm{g}) $$ Calculate $\Delta_{r} H^{\circ},$ the enthalpy change for this reaction, using the enthalpies of formation of $\mathrm{CO}_{2}(\mathrm{g}), \mathrm{H}_{2} \mathrm{O}(\ell)$ and $\mathrm{CHCl}_{3}(\mathrm{g})\left(\Delta_{f} H^{\circ}=-103.1 \mathrm{kJ} / \mathrm{mol}\right),$ and the enthalpy changes for the following reactions: Calculate $\Delta_{r} H^{\circ},$ the enthalpy change for this reaction, using the enthalpies of formation of $\mathrm{CO}_{2}(\mathrm{g}), \mathrm{H}_{2} \mathrm{O}(\ell)$ and $\mathrm{CHCl}_{3}(\mathrm{g})\left(\Delta_{f} H^{\circ}=-103.1 \mathrm{kJ} / \mathrm{mol}\right),$ and the enthalpy changes for the following reactions: