Consider a square potential, $U(x)=0$ for $x<-\alpha, U(x)=-U_{0}$ for $-\alpha \leq x \leq \alpha,$ where $U_{0}$ is a positive constant, and $U(x)=0$ for $x>\alpha .$ For $E>0,$ the solutions of the time-independent Schrödinger equation in the three regions will be the following:
For $x<-\alpha, \psi(x)=e^{i \kappa x}+R e^{-i \kappa x},$ where $\kappa^{2}=2 m E / \hbar^{2}$ and $R$ is the
amplitude of a reflected wave.
For $-\alpha \leq x \leq \alpha, \psi(x)=A e^{i \kappa^{\prime} x}+B e^{-i \kappa^{\prime} x},$ and $\left(\kappa^{\prime}\right)^{2}=2 m\left(E+U_{0}\right) / \hbar^{2}$
For $x>\alpha, \psi(x)=T e^{i \kappa x}$ where $T$ is the amplitude of the transmitted wave.
Match $\psi(x)$ and $d \psi(x) / d x$ at $-\alpha$ and $\alpha$ and find an expression for $R$. What is the condition for which $R=0$ (that is, there is no reflected wave)?