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Geometry

Ray C. Jurgensen,Richard G. Brown,John W. Jurgensen

Chapter 8

Right Triangles - all with Video Answers

Educators


Section 1

Similarity in Right Triangles

00:13

Problem 1

Simplify.
$$\sqrt{12}$$

Amrita Bhasin
Amrita Bhasin
Numerade Educator
00:15

Problem 2

Simplify.
$$\sqrt{72}$$

K B
K B
Numerade Educator
00:14

Problem 3

Simplify.
$$\sqrt{45}$$

Amrita Bhasin
Amrita Bhasin
Numerade Educator
00:17

Problem 4

Simplify.
$$\sqrt{75}$$

K B
K B
Numerade Educator
00:17

Problem 5

Simplify.
$$\sqrt{800}$$

Amrita Bhasin
Amrita Bhasin
Numerade Educator
00:14

Problem 6

Simplify.
$$\sqrt{54}$$

K B
K B
Numerade Educator
00:28

Problem 7

Simplify.
$$9 \sqrt{40}$$

Amrita Bhasin
Amrita Bhasin
Numerade Educator
00:19

Problem 8

Simplify.
$$4 \sqrt{28}$$

K B
K B
Numerade Educator
00:29

Problem 9

Simplify.
$$\sqrt{30} \cdot \sqrt{6}$$

Amrita Bhasin
Amrita Bhasin
Numerade Educator
00:24

Problem 10

Simplify.
$$\sqrt{5} \cdot \sqrt{35}$$

K B
K B
Numerade Educator
00:17

Problem 11

Simplify.
$$\sqrt{\frac{3}{7}}$$

Amrita Bhasin
Amrita Bhasin
Numerade Educator
00:21

Problem 12

Simplify.
$$\sqrt{\frac{9}{5}}$$

K B
K B
Numerade Educator
00:17

Problem 13

Simplify.
$$\frac{18}{\sqrt{3}}$$

Amrita Bhasin
Amrita Bhasin
Numerade Educator
00:23

Problem 14

Simplify.
$$\frac{24}{3 \sqrt{2}}$$

K B
K B
Numerade Educator
00:45

Problem 15

Simplify.
$$\frac{\sqrt{15}}{3 \sqrt{45}}$$

Amrita Bhasin
Amrita Bhasin
Numerade Educator
00:11

Problem 16

Find the geometric mean between the two numbers.
$$2 \text { and } 18$$

K B
K B
Numerade Educator
00:09

Problem 17

Find the geometric mean between the two numbers.
$$3 \text { and } 27$$

Amrita Bhasin
Amrita Bhasin
Numerade Educator
00:19

Problem 18

Find the geometric mean between the two numbers.
$$49 \text { and } 25$$

K B
K B
Numerade Educator
00:16

Problem 19

Find the geometric mean between the two numbers.
$$1 \text { and } 1000$$

Amrita Bhasin
Amrita Bhasin
Numerade Educator
00:30

Problem 20

Find the geometric mean between the two numbers.
$$16 \text { and } 24$$

K B
K B
Numerade Educator
00:17

Problem 21

Find the geometric mean between the two numbers.
$$22 \text { and } 55$$

Amrita Bhasin
Amrita Bhasin
Numerade Educator
00:23

Problem 22

Refer to the figure.
If $L M=4$ and $M K=8,$ find $J M.$

K B
K B
Numerade Educator
00:27

Problem 23

Refer to the figure.
If $L M=6$ and $J M=4,$ find $M K.$

Amrita Bhasin
Amrita Bhasin
Numerade Educator
00:34

Problem 24

Refer to the figure.
If $J M=3$ and $M K=6,$ find $L M$

K B
K B
Numerade Educator
00:24

Problem 25

Refer to the figure.
If $J M=4$ and $J K=9,$ find $L K$

Amrita Bhasin
Amrita Bhasin
Numerade Educator
00:38

Problem 26

Refer to the figure.
If $J M=3$ and $M K=9,$ find $L J$

K B
K B
Numerade Educator
00:36

Problem 27

Refer to the figure.
If $J M=3$ and $J L=6,$ find $M K$

Amrita Bhasin
Amrita Bhasin
Numerade Educator
01:13

Problem 28

Refer to the figure.
If $J L=9$ and $J M=6,$ find $M K$

K B
K B
Numerade Educator
00:43

Problem 29

Refer to the figure.
If $L K=3 \sqrt{6}$ and $M K=6,$ find $J M$

Amrita Bhasin
Amrita Bhasin
Numerade Educator
00:55

Problem 30

Refer to the figure.
If $L K=7$ and $M K=6,$ find $J M$

K B
K B
Numerade Educator
00:28

Problem 31

Find the values of $x, y,$ and $z.$

Amrita Bhasin
Amrita Bhasin
Numerade Educator
02:00

Problem 32

Find the values of $x, y,$ and $z.$

K B
K B
Numerade Educator
00:35

Problem 33

Find the values of $x, y,$ and $z.$

Amrita Bhasin
Amrita Bhasin
Numerade Educator
01:18

Problem 34

Find the values of $x, y,$ and $z.$

K B
K B
Numerade Educator
00:40

Problem 35

Find the values of $x, y,$ and $z.$

Amrita Bhasin
Amrita Bhasin
Numerade Educator
02:12

Problem 36

Find the values of $x, y,$ and $z.$

K B
K B
Numerade Educator
00:39

Problem 37

Find the values of $x, y,$ and $z.$

Amrita Bhasin
Amrita Bhasin
Numerade Educator
02:22

Problem 38

Find the values of $x, y,$ and $z.$

K B
K B
Numerade Educator
01:02

Problem 39

Find the values of $x, y,$ and $z.$

Amrita Bhasin
Amrita Bhasin
Numerade Educator
03:26

Problem 40

Prove Theorem $8-1.$

Ekaveera Kumar
Ekaveera Kumar
Numerade Educator
00:36

Problem 41

Refer to the figure at the right, and use Corollary 2 to complete:
$$a^{2}=\underline{?} \text { and } b^{2}=\underline{?}$$
b. Add the equations in part (a), factor the sum on the right, and show that $a^{2}+b^{2}=c^{2}$ .

Amrita Bhasin
Amrita Bhasin
Numerade Educator
03:19

Problem 42

Prove: In a right triangle, the product of the hypotenuse and the length of the altitude drawn to the hypotenuse equals the product of the two legs.

Suman Saurav Thakur
Suman Saurav Thakur
Numerade Educator
00:14

Problem 43

Given: $P Q R S$ is a rectangle;
$P S$ is the geometric mean between $S T$ and $T R .$
Prove: $\angle P T Q$ is a right angle.

Amrita Bhasin
Amrita Bhasin
Numerade Educator
02:29

Problem 44

Given: $P Q R S$ is a rectangle;
$$\angle A \text { is a right angle. }$$
Prove: $B S \cdot R C=P S \cdot Q R=(P S)^{2}$

Ekaveera Kumar
Ekaveera Kumar
Numerade Educator
01:39

Problem 45

The arithmetic mean between two numbers $r$ and $s$ is defined to be $\frac{r+s}{2}.$
a. $\overline{C M}$ is the median and $\overline{C H}$ is the altitude to the hypotenuse of right $\triangle A B C$ . Show that $C M$ is the arithmetic mean between $A H$ and $B H,$ and that $C H$ is the geometric mean between $A H$ and $B H .$ Then use the diagram to show that the arithmetic mean is greater than the geometric mean.
b. Show algebraically that the arithmetic mean between two different numbers $r$ and $s$ is greater than the geometric mean. (Hint: The geometric mean is $\sqrt{r s} .$ Work backward from $\frac{r+s}{2}>\sqrt{r s}$ to $(r-s)^{2}>0$ and then reverse the steps.)

Carson Merrill
Carson Merrill
Numerade Educator