When an electron scatters off an atom, the atom may be excited (or even ionised). Consider an electron scattering off a hydrogen atom. The Hamiltonian may be written as $H=H_{0}+H_{1}$ where
$$
H_{0}=\frac{\hat{\mathbf{p}}_{1}^{2}}{2 M}-\frac{e^{2}}{4 \pi \epsilon_{0} r_{1}}+\frac{\hat{\mathbf{p}}_{2}^{2}}{2 m}
$$
is the Hamiltonian of the hydrogen atom (of mass $M$ ) whose electron is described by coordinate $\mathbf{r}_{1}$, together with the kinetic Hamiltonian of the scattering electron (of mass $m$ ), while
$$
H_{1}=\frac{e^{2}}{4 \pi \epsilon_{0}}\left(\frac{1}{\left|\mathbf{r}_{1}-\mathbf{r}_{2}\right|}-\frac{1}{r_{2}}\right)
$$
is the interaction of the scattering electron with the atom.
By using $H_{0}$ in the evolution operators, show that in the Born approximation the amplitude for a collision to scatter the electron from momentum $\mathbf{p}_{2}$ to $\mathbf{p}_{2}^{\prime}$ whilst exciting the atom from the state $|n, l, m\rangle$ to the state $\left|n^{\prime}, l^{\prime}, m^{\prime}\right\rangle$ is
$$
\begin{aligned}
&f\left(\mathbf{p}_{2} ; n, l, m \rightarrow \mathbf{p}_{2}^{\prime} ; n^{\prime}, l^{\prime}, m^{\prime}\right) \\
&=-\frac{4 \pi^{2} \hbar m}{(2 \pi \hbar)^{3}} \int \mathrm{d}^{3} \mathbf{r}_{1} \mathrm{~d}^{3} \mathbf{r}_{2} \mathrm{e}^{-\mathrm{i} \boldsymbol{q}_{2} \cdot \mathbf{r}_{2}}\left\langle n^{\prime}, l^{\prime}, m^{\prime} \mid \mathbf{r}_{1}\right\rangle\left\langle\mathbf{r}_{1} \mid n, l, m\right\rangle H_{1}\left(\mathbf{r}_{1}, \mathbf{r}_{2}\right)
\end{aligned}
$$
where $\mathbf{q}_{2}$ is the momentum transferred to the scattering electron. (Neglect the possibility that the two electrons exchange places, and the recoil of the hydrogen atom.)
Compute the differential cross-section for the $|1,0,0\rangle \rightarrow|2,0,0\rangle$ transition and show that when the energy of the scattering particle is very high it varies as $\operatorname{cosec}^{12}(\theta / 2)$. Hint: perform the $\mathrm{d}^{3} \mathbf{r}_{2}$ integral by including a factor $\mathrm{e}^{-\alpha r_{2}}$ and then let $\alpha \rightarrow 0$.