$8 \mathrm{~g}$ of $\mathrm{NaOH}$ is dissolved in $18 \mathrm{~g}$ of $\mathrm{H}_{2} \mathrm{O} .$ Mole fraction of $\mathrm{NaOH}$ in solution and molality (in mol $\mathrm{kg}^{-1}$ ) of the solution respectively are :
[Main Jan. 12, 2019 (II)]
(a) $0.2,22.20$
(b) $0.2,11.11$
(c) $0.167,11.11$
(d) $0.167,22.20$