A standing wave is set up in a string of variable length and tension by a vibrator of variable frequency. Both ends of the string are fixed. When the vibrator has a frequency $f_{A},$ in a string of length $L_{A}$ and under tension $T_{A}, n_{A}$ anti-nodes are set up in the string. (a) Write an expression for the frequency $f_{A}$ of a standing wave in terms of the number $n_{A},$ length $L_{A},$ tension $T_{A},$ and linear density $\mu_{A} .$ If the length of the string is doubled to $L_{B}=2 L_{A},$ what frequency $f_{B}\left(\text { written as a multiple of } f_{A}\right)$ will result in the same number of antinodes? Assume the tension and linear density are unchanged. Hint: Make a ratio of expressions for $f_{B}$ and $f_{A}$ (c) If the frequency and length are held constant, what tension $T_{B}$ will produce $n_{A}+1$ antinodes? (d) If the frequency is tripled and the length of the string is halved, by what factor should the tension be changed so that twice as many anti-nodes are produced?