If the normal strain is defined in reference to the final length $\Delta s^{\prime}$, that is,
$$
\epsilon^{\prime}=\lim _{\Delta r^{\prime} \rightarrow 0}\left(\frac{\Delta s^{\prime}-\Delta s}{\Delta s^{\prime}}\right)
$$
instead of in reference to the original length, Eq. 2-2, show that the difference in these strains is represented as a second-order term, namely, $\epsilon-\epsilon^{\prime}=\boldsymbol{\epsilon} \epsilon^{\prime}$.