A rocket accelerates by burning its onboard fuel, so its mass decreases with time. Suppose the initial mass of the rocket at liftoff (including its fuel) is $m,$ the fuel is consumed at rate $r,$ and the exhaust gases are ejected with constant velocity $v_{e}$ (relative to the rocket). A model for the velocity of the rocket at time $t$ is given by the equation
$$v(t)=-g t-v_{c} \ln \frac{m-r t}{m}$$
where $g$ is the acceleration due to gravity and $t$ is not too large. If $g=9.8 \mathrm{m} / \mathrm{s}^{2}, m=30,000 \mathrm{kg}, r=160 \mathrm{kg} / \mathrm{s},$ and $v_{c}=3000 \mathrm{m} / \mathrm{s},$ find the height of the rocket one minute after liftoff.