A rocket accelerates by burning its onboard fuel, so its mass decreases with time. Suppose the initial mass of the rocket at liftoff (including its fuel) is $m$, the fuel is consumed at rate $r$, and the exhaust gases are ejected with constant velocity $v_{\varepsilon}$ (relative to the rocket). A model for the velocity of the rocket at time $t$ is given by the equation
$$
v(t)=-g t-v_e \ln \frac{m-r t}{m}
$$
where $g$ is the acceleration due to gravity and $t$ is not too large. If $g=9.8 \mathrm{~m} / \mathrm{s}^2, m=30,000 \mathrm{~kg}, r=160 \mathrm{~kg} / \mathrm{s}$, and $v_e=3000 \mathrm{~m} / \mathrm{s}$, find the height of the rocket one minute after liftoff.