Compound $A, C_{7} H_{14},$ decolorizes $\mathrm{Br}_{2}$ in $\mathrm{CH}_{2} \mathrm{Cl}_{2}$ and reacts with $\mathrm{BH}_{3}$ in THF followed by $\mathrm{H}_{2} \mathrm{O}_{2} / \mathrm{OH}^{-}$ to yield compound $B$. When treated with $\mathrm{KMnO}_{4}$, then $\mathrm{H}_{3} \mathrm{O}^{+}, B$ is oxidized to a carboxylic acid $C$ that can be resolved into enantiomers. Compound $A$, after ozonolysis and workup with $\mathrm{H}_{2} \mathrm{O}_{2},$ yields the same compound $D$ as is formed by the oxidation of 3 -hexanol with chromic acid. Identify compounds $A, B, C,$ and $D$.