Because $\mathrm{MB}=\frac{1}{2} \mathrm{BD}$ and $\mathrm{MA}=\mathrm{MC}=$
$\frac{1}{2} \mathrm{AC},$ it follows that $\mathrm{MB}=\mathrm{MA}=\mathrm{MC}$.
Why can a circle be drawn with center $\mathrm{M}$ and radius MA that goes through points $A, B,$ and $C ?$