Chapter Questions
What attributes make $\mathrm{XeF}_2$ a desirable fluorinating agent for organic compounds?
Which would you expect to be more stable, $\mathrm{NaXeF}_7$ or $\mathrm{CsXeF}_7$ ? Explain your answer.
One of the uses of helium is as an inert atmosphere during welding, especially of aluminum. From a chemical point of view, why is helium a more appropriate choice for this use than would be nitrogen?
Write complete balanced equations for the following.(a) $\mathrm{XeF}_4+\mathrm{SF}_4 \rightarrow$(b) $\mathrm{XeO}_3+\mathrm{OH}^{-} \rightarrow$(c) $\mathrm{XeF}_2+\mathrm{OH}^{-} \rightarrow$(d) $\mathrm{XeF}_2+\mathrm{P}_4 \rightarrow$(e) $\mathrm{XeF}_4+\mathrm{PtF}_5 \rightarrow$
If the $\mathrm{Kr}-\mathrm{F}$ bond enthalpy is $50 \mathrm{~kJ} \mathrm{~mol}^{-1}$ and the $\mathrm{F}-\mathrm{F}$ bond enthalpy is $159 \mathrm{~kJ} \mathrm{~mol}^{-1}$, what would be the heat of formation of gaseous $\mathrm{KrF}_2$ from the gaseous elements?
Draw structures for the following species.(a) $\mathrm{SbF}_6^{-}$(b) $\mathrm{XeO}_4$(c) $\mathrm{XeF}_3^{+}$(d) $\mathrm{XeF}_4$(e) $\mathrm{XeF}_5^{+}$
Discuss the role of multiple bonding in the $\mathrm{XeO}_4$ molecule.
Why is it possible for a molecule such as $\mathrm{XeF}_6$ or $\mathrm{N}_2 \mathrm{O}_5$ that exists as molecules in the gaseous state to take on a different nature in the solid state?
The Xe-F bond enthalpy is $133 \mathrm{~kJ} \mathrm{~mol}^{-1}$ and the $\mathrm{F}-\mathrm{F}$ bond enthalpy is $159 \mathrm{~kJ} \mathrm{~mol}^{-1}$. Calculate the heat of formation of gaseous $\mathrm{XeF}_2$ and $\mathrm{XeF}_4$.
If the lattice energy of $\mathrm{XeF}_4(s)$ is $62 \mathrm{~kJ} \mathrm{~mol}^{-1}$, what would be the enthalpy change for the following reaction?$$\mathrm{Xe}(g)+2 \mathrm{~F}_2(g) \rightarrow \mathrm{XeF}_4(s)$$C
Suppose it would be possible to synthesize $\operatorname{ArF}_2(g)$ even if it had a heat of formation of $+100 \mathrm{~kJ} \mathrm{~mol}^{-1}$. What would the Ar-F bond enthalpy have to be to make the synthesis possible if the F-F bond enthalpy is $159 \mathrm{~kJ} \mathrm{~mol}^{-1}$ ?
Given the fact that the Xe-F bond enthalpy is $133 \mathrm{~kJ} \mathrm{~mol}^{-1}$ and the $\mathrm{Kr}-\mathrm{F}$ bond enthalpy is only $50 \mathrm{~kJ} \mathrm{~mol}^{-1}$, comment on the possibility of preparing $\mathrm{ArF}_2$ and $\mathrm{NeF}_2$.
Explain why the bond lengths in the $\mathrm{Xe}_2 \mathrm{~F}_3{ }^{+}$ion are unequal as shown in the following structure: