In a copper voltameter, the mass deposited in $30 \mathrm{~s}$ is $m$ gram. If the current time graph is as shown in the figure, the e.c.e. of copper, in gm/coul, will be
(Figure can't copy)
(a) $m$
(b) $\frac{m}{2}$
(c) $0.6 \mathrm{~m}$
(d) $0.1 \mathrm{~m}$