If $x \sin a+y \sin 2 a+z \sin 3 a=\sin 4 a x \sin b+$
$y \sin 2 b+z \sin 3 b=\sin 4 b x \sin c+y \sin 2 c+z$
$\sin 3 c=\sin 4 c$, then the roots of the equation $t^{3}-\frac{z}{2} t^{2}-\frac{y+2}{4}+\frac{z-x}{8}=0 ; a, b, c \neq n \pi$, are
(A) $\sin a, \sin b, \sin c$
(B) $\cos a, \cos b, \cos c$
(C) $\sin 2 a, \sin 2 b, \sin 2 c$
(D) $\cos 2 a, \cos 2 b, \cos 2 c$