Non-orthogonal curvilinear coordinates are difficult to work with and should be avoided if at all possible, but the following example is provided to illustrate the content of section $10.10$
In a new coordinate system for the region of space in which the Cartesian coordinate $z$ satisfies $z \geq 0$, the position of a point $\mathbf{r}$ is given by $\left(\alpha_{1}, \alpha_{2}, R\right)$, where $\alpha_{1}$ and $\alpha_{2}$ are respectively the cosines of the angles made by $\mathbf{r}$ with the $x$ - and $y-$ coordinate axes of a Cartesian system and $R=|\mathbf{r}| .$ The ranges are $-1 \leq \alpha_{i} \leq 1$, $0 \leq R<\infty$
(a) Express $\mathbf{r}$ in terms of $\alpha_{1}, \alpha_{2}, R$ and the unit Cartesian vectors $\mathbf{i}, \mathbf{j}, \mathbf{k}$.
(b) Obtain expressions for the vectors $\mathbf{e}_{i}\left(=\partial \mathbf{r} / \partial \alpha_{1}, \ldots\right)$ and hence show that the scale factors $h_{i}$ are given by
$$
h_{1}=\frac{R\left(1-\alpha_{2}^{2}\right)^{1 / 2}}{\left(1-\alpha_{1}^{2}-\alpha_{2}^{2}\right)^{1 / 2}}, \quad h_{2}=\frac{R\left(1-\alpha_{1}^{2}\right)^{1 / 2}}{\left(1-\alpha_{1}^{2}-\alpha_{2}^{2}\right)^{1 / 2}}, \quad h_{3}=1
$$
(c) Verify formally that the system is not an orthogonal one.
(d) Show that the volume element of the coordinate system is
$$
d V=\frac{R^{2} d \alpha_{1} d \alpha_{2} d R}{\left(1-\alpha_{1}^{2}-\alpha_{2}^{2}\right)^{1 / 2}}
$$
and demonstrate that this is always less than or equal to the corresponding expression for an orthogonal curvilinear system.
(e) Calculate the expression for $(d s)^{2}$ for the system, and show that it differs from that for the corresponding orthogonal system by
$$
\frac{2 \alpha_{1} \alpha_{2} R^{2}}{1-\alpha_{1}^{2}-\alpha_{2}^{2}} d \alpha_{1} d \alpha_{2}
$$